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Every morning Ramona misses her bus with probability 1/10, independently of other mornings. What is the probability that next week she catches her bus on Monday, Tuesday, and Thursday, but misses her bus on Wednesday and Friday

Sagot :

Numenius

Answer:

The probability is [tex]\frac{729}{100000}[/tex].

Step-by-step explanation:

probability of missing the bus = 1/10

Probability of catching the bus = 1 - 1/10 = 9 /10

So, the required probability is

[tex]\frac{9}{10}\times \frac {9}{10}\times \frac {1}{10}\times \frac {9}{10}\times \frac {1}{10}[/tex]

[tex]\frac{729}{100000}[/tex]

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