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CH4+xO2=CO2+2H2O. Find x

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sbcardinals

Answer:

x = 2, [tex]CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\[/tex]

Explanation:

This question is related to balancing chemical equations.

[tex]CH_{4} + xO_{2} = CO_{2} + 2H_{2}O\\[/tex]

- There must be the same amount of carbons (C), hydrogens (H), and oxygens (O) on each side of the equals sign.

- There is already 1 carbon and 4 hydrogens on each side of the equals sign. The big number in front of the chemical compound multiplies into the individual elements and can be multiplied by the subscripts to get the total number of each element.

- On the right side of the equation, there are 4 oxygens (O), and on the left side, there are 2. In order for there to be 4 oxygens (O) on the left side, there must be a 2 in front of [tex]O_{2}[/tex].

Therefore, x = 2.

[tex]CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\[/tex]

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