Answered

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Solve 2x^2
+ x - 4= 0.
x2 +
= 0
DONE

Sagot :

[tex]\\ \sf\longmapsto 2x^2+x-4=0[/tex]

[tex]\\ \sf\longmapsto 2x^2+x=4[/tex]

[tex]\\ \sf\longmapsto 8(2x^2+x=4)[/tex]

[tex]\\ \sf\longmapsto 16x^2+8x=32[/tex]

[tex]\\ \sf\longmapsto (4x)^2+2(4x)(1)=32[/tex]

[tex]\\ \sf\longmapsto 4x^2+2(4x)(1)+1^2=32+1^2[/tex]

[tex]\\ \sf\longmapsto (4x+1)^2=33[/tex]

[tex]\\ \sf\longmapsto 4x+1=\pm\sqrt{33}[/tex]

[tex]\\ \sf\longmapsto 4x=-1\pm\sqrt{33}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-1\pm\sqrt{33}}{4}[/tex]

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