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A. What is the change in internal energy for each of the following situations? q = 7.9 J out of the system and w = 3.6 J done on the system q = 1.5 J into the system and w = 7.5 J done on the system

Sagot :

Answer: [tex]-4.3\ J,\ 9\ J[/tex]

Explanation:

Given

(a)

Heat transfer [tex]Q=-7.9\ J\quad \text{taken}[/tex]

Work done [tex]W=-3.6\ J\quad \text{on the system}[/tex]

Change in the internal kinetic energy is

[tex]\Delta U=Q-W\\\Rightarrow \Delta U=-7.9-(-3.6)\\\Rightarrow \Delta U=-4.3\ J[/tex]

(b)

Heat transfer [tex]Q=1.5\ J\quad \text{given}[/tex]

Work done [tex]W=-7.5\ J\quad \text{on the system}[/tex]

Change in the internal kinetic energy is

[tex]\Delta U=Q-W\\\Rightarrow \Delta U=1.5-(-7.5)\\\Rightarrow \Delta U=9\ J[/tex]

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