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Given the function h(x)=-x^2 + X+4 determine the average rate of change of function over interval -1< x < 5

Sagot :

Answer:

- 3

Step-by-step explanation:

The average rate of change of h(x) in the closed interval [ a, b ] is

[tex]\frac{h(b)-h(a)}{b-a}[/tex]

Here [ a, b ] = [ - 1, 5 ] , then

h(b) = h(5) = - 5² +  5 + 4 = - 25 + 9 = - 16

h(a) = h(- 1) = - (- 1)² + (- 1) + 4 = - 1 - 1 + 4 = 2

average rate of change = [tex]\frac{-16-2}{5-(-1)}[/tex] = [tex]\frac{-18}{6}[/tex] = - 3

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