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Suppose the height of a ball in feet is given by the quadratic equation below, where T is in seconds. What expression will give the time when the ball reaches its maximum height? h=-16t^2+50t+8. Please look at the image for the available answers. Thank you.

Suppose The Height Of A Ball In Feet Is Given By The Quadratic Equation Below Where T Is In Seconds What Expression Will Give The Time When The Ball Reaches Its class=

Sagot :

Answer:

t = -50/(2 * (-16))

Step-by-step explanation:

For quadratics of the form

y = ax^2 + bx + c

the x coordinate of the vertex is

x = -b / 2a

----------------------

h = -16t^2 +50t + 8

a = -16

b = 50

t at Vertex

t = -50/(2 * (-16))

View image Аноним
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