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Sagot :
The limit of x approaching infinite of a function gives it's horizontal assymptote. We use this to solve the question, getting the following answer:
Because Limit of f (x) as x approaches plus-or-minus infinity = 16, the function has a horizontal asymptote at y = 16.
Horizontal asymptote:
An horizontal asymptote is the value of y given by:
[tex]y = \lim_{x \rightarrow \infty} f(x)[/tex]
In this question:
[tex]f(x) = \frac{16x^2 - 35}{x^2 - 5}[/tex]
The horizontal asymptote is:
[tex]y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{16x^2 - 35}{x^2 - 5}[/tex]
Considering it is a limit of x going to infinite, we just consider the terms with the highest exponents both in the numerator and in the denominator, so:
[tex]y = \lim_{x \rightarrow \infty} \frac{16x^2 - 35}{x^2 - 5} = \lim_{x \rightarrow \infty} \frac{16x^2}{x^2} = \lim_{x \rightarrow \infty} 16 = 16[/tex]
Thus, the correct answer is:
Because Limit of f (x) as x approaches plus-or-minus infinity = 16, the function has a horizontal asymptote at y = 16.
From the graph of the function, given at the end of this answer, you can check that as x goes to infinity, y(green line) approches 16(blue line).
For more on infinite limits, you can check https://brainly.com/question/23335924
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