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Sagot :
Answer:
Step-by-step explanation:
x²-8x+16+y²+2y+1=16+1-13
(x-4)²+(y+1)²=2²
general form of a circle's equation is
(x-h)^2 + (y-k)^2 = r^2
Where (h,k) is the center and r= radius
By comparing with A,
(4,-1) is center and radius= 2.
The center of the circle is (-4,2) and the radius is 2
How to determine the center and the radius?
The equation is given as:
x^2 + y^2 - 8x + 2y + 13 = 0
Rewrite as:
x^2 - 8x + y^2 + 2y + 13 = 0
Subtract 12 from both sides
x^2 - 8x + y^2 + 2y = -13
Group each variable
[x^2 - 8x] + [y^2 + 2y] = -13
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Take the coefficient of x and y
-8 and 2
Divide by 2
-4 and 1
Square both numbers
16 and 1
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Next, we add 16 and 1 to both sides of the equation
[x^2 - 8x + 16] + [y^2 + 2y + 1] = -13 + 16 + 1
Express as perfect squares and evaluate the sum
(x - 4)^2 + (y + 1)^2 = 4
Express 4 as 2^2
(x - 4)^2 + (y + 1)^2 = 2^2
A circle is represented as:
(x - a)^2 + (y - b)^2 = r^2
Where:
Center = (a,b)
Radius = r
This means that the center of the circle is (-4,2) and the radius is 2
Read more about circle equation at:
https://brainly.com/question/1559324
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