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A person places $3090 in an investment account earning an annual rate of 3%, compounded continuously. Using the formula V = Pe^{rt}V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 11 years.

Sagot :

Answer:

V=4298.0915\approx 4298.09

V=4298.0915≈4298.09

Step-by-step explanation:

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