SpicyMilk
Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A rock is thrown from the top of a building . The height, h, of the rock t seconds after it thrown is given by h(t) = - 16t ^ 2 - 2t + 240 . How long will it take the rock to reach a height of 180 feet?

Sagot :

Answer:

1.875 sec

Step-by-step explanation:

Let h(t) = 180

180 = -16t^2 - 2t + 240

16t^2 + 2t - 60 = 0

2(8t^2 + t - 30) = 0

2(t + 2)(8t - 15) = 0

t = -2  or t = 15/8= 1.875 sec

Note:  time cannot be negative, so -2 is disregarded

shubhamchouhanvrVT

The time is taken by the rock to reach the height of 180 feet is 1.875 sec

What is an equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

The solution will be:-

Let h(t) = 180

180 = -16t²- 2t + 240

16t² + 2t - 60 = 0

2(8t² + t - 30) = 0

2(t + 2)(8t - 15) = 0

t = -2  or t = 15/8= 1.875 sec

Therefore the time is taken by the rock to reach the height of 180 feet is 1.875 sec

To know more about equations follow

https://brainly.com/question/2972832

#SPJ2

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.