Answered

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A negative charge of -0.00040 C and a positive charge of 0.00092 C are separated by 0.4 m. What is the force between the two charges?

Sagot :

asuwafohjames

Answer:

20654 N

Explanation:

Applying

F = kqq'/r²........... equation 1

Where F = Force between the charge, q = First charge, q' = second charge, r = distance betweeen the charge, k = coulomb's constant.

From the question,

Given: q = -0.0004 C, q' = 0.00092 C, r = 0.4 m

Constanr: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

F = ( -0.0004×0.00092×8.98×10⁹)/(0.4²)

F = (3.30464×10³)/0.16

F = (3304.64)/0.16

F = 20654 N

Hence the force between the charges is 20654 N

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