Answered

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Find an
equation for the line through (-6, 3) and
parallel to y = 3x + 1.

Sagot :

Since this line is parallel to y = 3x + 1 their slopes are equal. The slope is equal to 3. The line is also passing the point (-3,4).

This is the format of the line parallel to y = 3x + 1

y = 3x+ b

This line passes through point (-3, 4)

Replacing the values of y and x coming from the coordinates of (-3, 4)

4 = 3 * (-3) + b

Solving for the y-intercept b

4 = -9 + b

b = 4 + 9

b = 13

Knowing the slope as equal to 3 and the y-intercept as 13 the equation of the line is

y = 3x+13

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