Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

1) What is the value of G at 120.0 K for a reaction in which H = +35 kJ/mol and S = 1.50
kJ/(mol.K)?

Sagot :

jufsanabriasa

Answer:

ΔG = -145kJ/mol

Explanation:

To solve this question we must use the change in Gibbs free energy:

ΔG = ΔH - TΔS

Where ΔG is change in Gibbs free energy = ?

ΔH is enthalpy change = +35kJ/mol

T is absolute temperature = 120.0K

And ΔS is change in entropy = 1.50kJ/molK

Replacing:

ΔG = 35kJ/mol - 120.0K*1.50kJ/molK

ΔG = 35kJ/mol - 180kJ/mol

ΔG = -145kJ/mol

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.