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A jar contains five blue marbles and two red marbles. Suppose you choose a marble at random, and do not replace it. Then you choose a second marble. Find the probability of the following even
Both of the selected marbles are red

Sagot :

Answer:

[tex]\frac{1}{21} = 0.0476[/tex] probability that both marbles are red.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Find the probability that both of the selected marbles are red

First marble: 2 red from a set of 5 + 2 = 7

Second marble: 1 red from a set of 6.

So

[tex]p = \frac{2}{7}*\frac{1}{6} = \frac{2}{42} = \frac{1}{21} = 0.0476[/tex]

[tex]\frac{1}{21} = 0.0476[/tex] probability that both marbles are red.

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