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Need help ASAP! I’ll give brainliest;) No links please, will report.

The perimeter of a triangle is 5x^4+5x^3+5x^2+50x+100. One side is 5x^2+103x+40 and the other side is 5x^3-43+100. What is the length of the third side of the triangle?

Sagot :

msm555

Answer:

side 1=5x^2+103x+40

side2=5x^3-43+100

side 3=A {let}

we have

perimeter of triangle=side 1+ side2 +side3

5x^4+5x^3+5x^2+50x+100=5x^2+103x+40+5x^3-

43+100+A

A=5x⁴+5x³+5x²+50x+100-5x³-5x²-103x-97

A=5x⁴-53x+3 is your answer

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