Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A pump lifts 260 kg of water per hour a height of 3.5 m . What is the minimum necessary power output rating of the water pump in watts? Express your answer using two significant figures.

Sagot :

Answer:

2.5 Watts.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 260 Kg

Time (t) = 1 h

Height (g) = 3.5 m

Power (P) =.?

Next, we shall determine the energy. This can be obtained as follow:

Mass (m) = 260 Kg

Height (g) = 3.5 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E) =?

E = mgh

E = 260 × 10 × 3.5

E = 9100 J

Finally, we shall determine the power. This can be obtained as follow:

Time (t) = 1 h = 3600 s

Energy (E) = 9100 J

Power (P) =.?

P = E/t

P = 9100 / 3600

P = 2.5 Watts

Thus, the power is 2.5 Watts.

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.