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At a point on the ground 50 feet from the foot of
a tree, the angle of elevation to the top of the tree is 53º. Find
the height of the tree.

Sagot :

EMEGroup

Answer:

[tex] \tan(53) = \frac{x}{50} \\ x = \tan(53) \times 50 \\ x = 66.35 \: feet[/tex]

Step-by-step explanation:

I hope that is useful for you :)

View image EMEGroup
ashishdwivedilVT

The height of the tree with angle of elevation of 53⁰ is 66 ft.

What is Angle of Elevation?

The angle of elevation is the angle between the horizontal line of sight and the object.

Here,  Let the height of the tree be x ft.

          The angle of elevation = 53⁰

          Distance from ground = 50 ft.

According to question,

        tan 53⁰ = x/50

         x = 50 × tan 53⁰

         x = 50 X 1.32

         x = 66 ft.

Thus, the height of the tree with angle of elevation of 53⁰ is 66 ft.

Learn more about Angle of elevation from:

https://brainly.com/question/16716174

#SPJ2

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