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Complete the square to go to the conic form of the circle. x^{2}+y^{2}+8x-2y+1=0

Sagot :

tellvinaykr

Answer:

Step-by-step explanation:

[tex]x^2+8x+y^2-2y=-1\\\\x^2+8x+16+y^2-2y+1=-1+16+1\\(x+4)^2+(y-1)^2=16\\\\(x+4)^2+(y-1)^2 = 4^2[/tex]

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