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Sagot :
Answer:
1 ladrillo cuesta 1 dólar. 1 brick costs 1 dollars.
1 kg de cemento cuesta 3 dólares: 1 kg cement costs 3 dollars
1 kg de arena cuesta $ 16: 1 kg sand costs $ 16
Step-by-step explanation:
Spanish
Deje que los ladrillos, la arena y el cemento se denoten por b, sy c. Luego, de acuerdo con la condición dada
20b + 5s + 10c = $ 130 --- ecuación 1
1c = 3b ------ ecuación 2
1s = 4c + 4b ------ ecuación 3
Poniendo la ecuación 2 en la ecuación 3
1s = 4 (3b) + 4b
1s = 16b ---------- ecuación 4
20b + 5s + 10 (3b) = $ 130
50b + 5s = 130 --- ecuación 5
Poniendo la ecuación 4 en la ecuación 5
50 b + 5 (16b) = 130
50 b + 80b = 130
130 b = 130
b = 130/130 = $ 1 ------- ecuación a
1 ladrillo cuesta 1 dólar.
Poner el valor de costo de 1 ladrillo en estas ecuaciones
1c = 3b ------ ecuación 2
1s = 4c + 4b ------ ecuación 3
1c = 3 (1) = $ 3 -------- ecuación b
1 kg de cemento cuesta 3 dólares
1s = 4c + 4b
1 s = 4 (3) + 4 (1)
1 s = 12 + 4
1s = $ 16 ------ ecuación c
1 kg de arena cuesta $ 16
Poner valores de la ecuación a, b, c en la ecuación 1
20b + 5s + 10c = $ 130
20 (1) + 5 (16) + 10 (3) = 130
20 + 80 + 30 = 130
130 = 130 ------------ por lo tanto probado
English
Let the bricks , sand and cement be denoted by b, s and c. Then according to the given condition
20b+ 5s+ 10c= $130--- equation 1
1c= 3b------ equation 2
1s= 4c+4b------ equation 3
Putting equation 2 in equation 3
1s= 4(3b) + 4b
1s= 16b---------- equation 4
20b+ 5s+ 10(3b)= $130
50b + 5s= 130--- equation 5
Putting equation 4 in equation 5
50 b + 5 (16b) = 130
50 b+ 80b= 130
130 b= 130
b= 130/130= $1------- equation a
1 brick costs 1 dollars.
Putting the cost value of 1 brick in these equations
1c= 3b------ equation 2
1s= 4c+4b------ equation 3
1c= 3(1)= $3-------- equation b
1 kg cement costs 3 dollars
1s= 4c+4b
1s= 4(3) + 4(1)
1s= 12+4
1s= $16 ------ equation c
1 kg sand costs $ 16
Putting values from equation a, b, c in equation 1
20b+ 5s+ 10c= $130
20 (1) + 5 (16) + 10 (3)= 130
20 + 80 + 30 = 130
130 = 130 ------------ hence proved
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