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In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

Sagot :

Answer:

90,597 square inches

Step-by-step explanation:

In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

We solve using Heron's formula

A = √s(s -a)(s - b) (s - c)

s = a + b + c/2

a = 410 inches

b = 530 inches

c = 830 inches

Hence,

s = 410 + 530 + 830/2

s = 885

A = √885(885 - 410)(885 - 530)(885 - 830)

A = 90,597.030166557 square inches

Approximately = 90,597.0 square inches

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