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Sagot :
Answer:
a.
• The population is normally distributed
• The 7 subjects represent a random sample from this population
b. True
c. 74.16%
Step-by-step explanation:
on using data [649, 832, 41 8, 530, 384, 899, 755] (please correct if wrong)
sample mean: 638.143
s: 201.72
Sample Mean = 638.143
SD = 201.72
Sample Size (n) = 7
Standard Error (SE) = SD/root(n) = 76.243
alpha (a) = 1-0.9 = 0.1
we use t-distribution as population standard deviation is unknown t(a/2, n-l ) = 1.9432
Margin of Error (ME) = SE = 148.1554
90% confidence interval is given by: Sample Mean +/- (Margin of Error) 638.143 +/- 148.1554 = (489.9876 , 786.2984)
• The population is normally distributed
• The 7 subjects represent a random sample from this populatio
(b) true, this is the definition of Cl
(c) (41 8, 432) has width = 14
hence, Margin of error = 7
sorted data is 384, 418, 530, 649, 755, 832, 899
Here 418 and 432 are 2nd and 6th entry of sample size of 7
Since median is given by (1 + n/2 + z(alpha/2)*sqrt(n) /2 )th entry on the right, we conclude that 1 + (3.5 + this gives z = 1.1339 ==> alpha = 0.2584
Hence this Cl is of 74.16% (approximately)
Note that your course might have given a different formula for calculating Cl medians from sample.
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