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What is the surface area of the cylinder with height 5 mi and radius 6 mi? Round your answer to the nearest thousandth.

Sagot :

tanweeleong195oxyqwp

Step-by-step explanation:

Given

h = 5 mi

r = 6 mi

Surface Area of Cylinder =

[tex]2\pi \: rh + 2\pi {r}^{2} \\ = 2\pi(6)(5) + 2\pi ({6}^{2}) \\ = 2\pi(30) + 2\pi(36) \\ = 60\pi + 72\pi \\ = 132\pi \\ = 414.690 {mi}^{2} (nearest \: thousandth)[/tex]

Yoyogr

Answer: 414.69 m2

Step-by-step explanation:

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