Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Cylinder A has radius r and height h as shown in the diagram. Cylinder B has radius 2r and height 2h. How many times greater is the surface area of Cylinder B than the surface area of Cylinder A?
I will ONLY give you a brainliest of you answer this questions CORRECTLY!

Cylinder A Has Radius R And Height H As Shown In The Diagram Cylinder B Has Radius 2r And Height 2h How Many Times Greater Is The Surface Area Of Cylinder B Tha class=

Sagot :

cairde

Answer:

Therefore, Cylinder B's surface area is four times greater than Cylinder A's surface area.

Step-by-step explanation:

Surface area of a cylinder = 2πrh+2πr² = 2π(rh+r²)

Cylinder A = 2π(rh+r²)

Cylinder B = 2π((2r)(2h)+(2r)²) = 2π(4rh+4r²)=2π(4(rh+r²))

To find how many times greater Cylinder B's surface area is than Cylinder A's surface area, divide:

[tex]\frac{Cylinder B}{Cylinder A}[/tex]

=2π(4(rh+r²))/2π(rh+r²)

(divide top and bottom by 2π)

=4(rh+r²)/(rh+r²)

(divide top and bottom by (rh+r²))

=4

Therefore, Cylinder B's surface area is four times greater than Cylinder A's surface area.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.