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A block of iron has dimensions of 1 cm x 2 cm x 5 cm and has a
mass of 799
What is its density? (V=lxwxh)


Sagot :

Answer:

79.9 units

Step-by-step explanation:

Hi there,

Before solving this problem, it is important to know the formula:

D = [tex]\frac{m}{v}[/tex].

D = density

m = mass

v = volume

Since we are given the mass and volume, we can simply enter these values into the formula to find the density of the block.

D = [tex]\frac{799}{10}[/tex]

D = 79.9

Therefore, the density of the block of iron is 79.9 units. I wrote units since you did not specify the unit for the mass. Hope this answer and explanation helps.

Cheers.

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