Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Consider the derivation of the quadratic formula below. What is the missing radicand

in Step 6?

Sagot :

MrRoyal

Answer:

[tex]\frac{b^2 - 4ac}{4a^2}[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required:

Complete step 6

At step 5, we have:

[tex](x + \frac{b}{2a})^2 = \frac{b^2}{4a^2} - \frac{4ac}{4a^2}[/tex]

Take LCM

[tex](x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2}[/tex]

Take square roots of both sides to get step 6

[tex]x + \frac{b}{2a} = \±\sqrt{\frac{b^2 - 4ac}{4a^2}}[/tex]

Hence, the missing radicand is: [tex]\frac{b^2 - 4ac}{4a^2}[/tex]

View image MrRoyal
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.