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What will be the pH of a buffer solution containing an acid of pKa7.5, with an acid concentration exactly one fourth of that of the conjugate base

Sagot :

Answer: pH of buffer solution is 8.1

Explanation:

The formula for the Henderson–Hasselbalch equation is:

[tex]pH=pK_a+\log\frac{[A^-]}{[HA]}[/tex]

[tex]pH[/tex] is the concentration of [tex][H^+][/tex]

[tex]pK_a[/tex] is the acid dissociation constant,

[tex]A^-[/tex] and [tex]HA[/tex] are concentrations of the conjugate base and starting acid.

Putting in the values we get:

[tex]pH=7.5+\log\frac{x}{\frac{x}{4}}[/tex]

[tex]pH=8.1[/tex]

Thus pH of buffer solution is 8.1

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