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Write the equation of a circle whose diameter is 12 and whose center is at (-6,-3)?

Sagot :

sqdancefan

Answer:

  (x +6)² +(y +3)² = 36

Step-by-step explanation:

The standard form equation of a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

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We have a circle with diameter 12, so its radius is 6. The center is given as (h, k) = (-6, -3), so the equation can be written ...

  (x -(-6))² +(y -(-3))² = 6²

Simplifying this a suitable amount, we have the equation ...

  (x +6)² +(y +3)² = 36

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