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Instructions:Write the equation of the line with a slope of 3/4 and a y-intercept of -7 in Slope-Intercept and Point-Slope Form.


Sagot :

Answer:

slope form = y= 3/4x -7

point slope= y-(-3) = 3/4(x-3) or y-(-4)= 3/4(x-4)

Step-by-step explanation:

slope form = y= mx + b

y = 3/4x - 7

point-slope form = y - y1 = m(x - x1)

step 1. Substitute a convenient value of x into your equation and solve for y (You're doing this to get the point x1,y1). Let's choose x=3. Yes, you could choose x=4.

y= 3/4x - 7

if you choose x = 3

y=3/4(3) - 7

y = 4 -7

y = -3

(x1,y1) = (3,-3)

if you choose x = 4l

y= 3/4(4) - 7

y = 3 - 7

y = -4

(x1,y1)= (4, -4)

step 2. Substitute the point you found , (x1, y1) , into the point slope formula.

if you choose x=3

y-y1=m(x-x1)

y-(-3) = 3/4(x- 3)

if you choose x = 4

y- y1 = m(x-x1)

y - (-4) = 3/4(x-4)

brainliest is appreciated