Answered

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cos(alpha + pi/3) = (sqrt(3))/2

Sagot :

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Answer:

α = -2 π n_1 - π/2 for n_1 element Z

or α = -2 π n_2 - π/6 for n_2 element Z

Step-by-step explanation:

Solve for α:

sin(-α + π/6) = sqrt(3)/2

Hint: | Eliminate the sine from the left hand side.

Take the inverse sine of both sides:

-α + π/6 = 2 π n_1 + (2 π)/3 for n_1 element Z

or -α + π/6 = 2 π n_2 + π/3 for n_2 element Z

Hint: | Look at the first equation: Isolate terms with α to the left hand side.

Subtract π/6 from both sides:

-α = 2 π n_1 + π/2 for n_1 element Z

or -α + π/6 = 2 π n_2 + π/3 for n_2 element Z

Hint: | Solve for α.

Multiply both sides by -1:

α = -2 π n_1 - π/2 for n_1 element Z

or -α + π/6 = 2 π n_2 + π/3 for n_2 element Z

Hint: | Look at the second equation: Isolate terms with α to the left hand side.

Subtract π/6 from both sides:

α = -2 π n_1 - π/2 for n_1 element Z

or -α = 2 π n_2 + π/6 for n_2 element Z

Hint: | Solve for α.

Multiply both sides by -1:

Answer: α = -2 π n_1 - π/2 for n_1 element Z

or α = -2 π n_2 - π/6 for n_2 element Z

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