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Step-by-step explanation:

a) First we will convert 150km/hr to m/s.

[tex] \frac{150km}{1hr} = \frac{(150 \times 1000)m}{(1 \times 60)s} \\ = \frac{150000m}{60s} \\ = 2500m \: per \: second[/tex]

=2500m/s, which is the initial speed of the plane.

b)Final Speed of plane = Speed when it stopped.

= 0m/s.

c)Time taken to stop = 3 seconds.

d)Using the kinematic equation,

v = u + at,

where v = Final Speed = 0m/s

u = Initial Speed = 2500m/s

a = acceleration

t = time taken = 3 seconds

Substitute v, u and t to find a.

[tex]0 = 2500 + 3a \\ 3a = - 2500 \\ a = - 2500 \div 3 \\ = - 833 \frac{1}{3} \frac{m}{ {s}^{2} } [/tex]

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