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What is the volume (in liters) of a 5.98 gram sample of O2 at STP?


Sagot :

Answer:

4.186 L

Explanation:

Using the pv=nrt equation and converting the grams of O2 into mols. After finding the number of mols by dividing 5.98 by 32 (2*the atomic weight of O) you plug that into the equation. So then you have 1*V=.186875*.08206*273 then you rearrange the equation to solve for v and get 4.186 L

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