Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

calculate the [H3O+] of 0.35 M solution of benzoic acid, HC7H3O2

Sagot :

jufsanabriasa

Answer:

4.70x10⁻³ = [H₃O⁺]

Explanation:

The Ka of benzoic acid is 6.3x10⁻⁵

The aqueous equilibrium of benzoic acid with its conjugate base could be written as:

HC₇H₃O₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + C₇H₃O₂(aq)

Where Ka is defined as:

Ka = 6.3x10⁻⁵ = [C₇H₃O₂] [H₃O⁺] / [HC₇H₃O₂]

As both H⁺ and C₇H₃O₂ are obtained from the same equilibrium:

[C₇H₃O₂] = [H₃O⁺]

And as [HC₇H₃O₂] = 0.35M we can write:

6.3x10⁻⁵ = [H₃O⁺] [H₃O⁺] / [0.35M]

2.205x10⁻⁵ = [H₃O⁺]²

4.70x10⁻³ = [H₃O⁺]

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.