Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The reaction for the decomposition of ammonia (NH 3 ) can be written as shownIf a student starts with 95.7 g of NH 3 , how many grams of hydrogen (H 2 ) will be produced by the reaction?

Sagot :

dsdrajlin

Answer:

17.0 g

Explanation:

Step 1: Write the reaction for the decomposition of ammonia

2 NH₃(g) ⇒ N₂(g) + 3 H₂(g)

Step 2: Calculate the moles corresponding to 95.7 g of NH₃

The molar mass of NH₃ is 17.03 g/mol.

95.7 g × 1 mol/17.03 g = 5.62 mol

Step 3: Calculate the moles of H₂ produced from 5.62 moles of NH₃

The molar ratio of NH₃ to H₂ is 2:3. The moles of H₂ produced are 3/2 × 5.62 mol = 8.43 mol.

Step 4: Calculate the mass corresponding to 8.43 moles of H₂

The molar mass of H₂ is 2.02 g/mol.

8.43 mol × 2.02 g/mol = 17.0 g

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.