Answered

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An object has a volume of 4.0 m3 and weighs 40,000 N. What will its apparent weight be in water of density 1000 kg/m3?

Sagot :

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Answer:

O N

Explanation:

Upthrust = Volume of object * density of fluid * acceleration due to gravity

Upthrust = 4.0 m3 *  1000 kg/m3 * 10 m/^2

Upthrust = 40, 000 N

Upthrust = Weight in air - Weight in water

Weight in air = 40,000 N

Weight in water = Weight in air - Upthrust

Weight in water = 40,000 N - 40,000 N

Weight in water = 0 N

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