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Answered

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urgent please help. will mark brainliest.
[tex]given \: that \: p = {x}^{2} + 4x - 2 \: and \: q = 2x - 1 \: and \: q - p = 2 \: find \: x[/tex]
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Sagot :

Leora03

Answer:

x= -1

Step-by-step explanation:

p= x² +4x -2 -----(1)

q= 2x -1 ------(2)

q -p= 2 -----(3)

Substitute (1) and (2) into (3):

2x -1 -(x² +4x -2)= 2

2x -1 -x² -4x +2= 2 (Expand bracket)

-x² -2x +1=2 (Simplify)

x² +2x +2 -1= 0 (Bring all terms to one side)

x² +2x +1= 0

(x +1)²= 0 (Factorise)

x +1= 0 (Square root both sides)

x= -1 (-1 on both sides)

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