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please help need soon What is the perimeter of the triangle below?

Sagot :

tanweeleong195oxyqwp

Step-by-step explanation:

Use Sine Rule.

[tex] \frac{r}{ \sin(90) } = \frac{4.9}{ \sin(45) } \\ \: cross \: multiply \\ rsin(45) = 4.9sin(90) \\ r = \frac{4.9sin(90)}{ \sin(45) } \\ r = \frac{49 \sqrt{2} }{10} [/tex]

Use same rule to find n1.

[tex] \frac{n1}{sin45} = \frac{4.9}{sin(45)} \\ cross \: multiply \\ n1 \sin(45) = 4.9sin(45) \\ n1 = 4.9[/tex]

Therefore Perimeter of triangle = Sum of all sides.

[tex]r + n1 + 4.9 = \frac{49 \sqrt{2} }{10} + 4.9 + 4.9 \\ = \frac{49 \sqrt{2} }{10} + \frac{49}{5} [/tex]

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