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If 10.00 moles of copper are reacted with 6.00 moles of sulfur according to the following balanced equation, which reactant is the limiter and how many moles of excess reactant would remain after the reaction is completed? 2 Cu + S --> Cu2S



Cu is limiting and 1.00 mole of excess S remain


S is limiting and 1.00 moles of excess Cu remain


S is limiting and 4.00 moles of excess Cu remain


Cu is limiting and 4.00 moles of excess S remain

Sagot :

Answer: Cu is limiting and 1.00 mole of excess S remain

Explanation:

The chemical balanced reaction is:

[tex]2Cu+S\rightarrow Cu_2S[/tex]  

According to stoichiometry :

2 moles of [tex]Cu[/tex] require 1 mole of [tex]S[/tex]

Thus 10.00 moles of [tex]Cu[/tex] will require=[tex]\frac{1}{2}\times 10.00=5.00moles[/tex]  of [tex]S[/tex]

Thus [tex]Cu[/tex] is the limiting reagent as it limits the formation of product and [tex]S[/tex] is the excess reagent.

Moles of S left = (6.00-5.00) moles = 1.00 mole

Thus Cu is limiting and 1.00 mole of excess S remain.

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