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12.0 g NaHSO4 (MM: 120.1 g/mol) is dissolved in water to make a 2.00 L solution. What is the molarity of the resulting NaHSO4 solution?

Sagot :

maacastrobr

Answer:

0.05 M

Explanation:

First we convert 12 g of NaHSO₄ into moles, using the given molar mass:

  • 12 g NaHSO₄ ÷ 120.1 g/mol = 0.10 mol NaHSO₄

We can now calculate the molarity of the resulting solution, using the calculated number of moles and the given volume:

  • Molarity = moles / liters
  • Molarity = 0.10 mol / 2.00 L = 0.05 M

CintiaSalazar

Answer:

The molarity of the resulting NaHSO₄ solution is 0.05 [tex]\frac{moles}{liter}[/tex]

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

[tex]Molarity=\frac{moles of solute}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Molar mass is the amount of mass that a substance contains in one mole. Being the molar mass of the compound NaHSO₄ equal to 120.1 g/mole, then the number of moles that 12 grams contain is calculated by:

[tex]12 g*\frac{1 mole}{120.1 g} = 0.1 moles[/tex]

And being 2 L the volume of the solution, then replacing in the definition of molarity you get:

[tex]Molarity=\frac{0.1 moles}{2 L}[/tex]

Molarity= 0.05 [tex]\frac{moles}{liter}[/tex]

The molarity of the resulting NaHSO₄ solution is 0.05 [tex]\frac{moles}{liter}[/tex]

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