Answer:
x = 3, y = 5
or (3,5) in coordination point form.
Step-by-step explanation:
We are going to solve the system of equations by combining two equations. To do that, we isolate y-term.
[tex] \large{\begin{cases} 5x - y = 10 \\ 3x + y = 14 \end{cases}}[/tex]
Convert both equations to slope-intercept form.
[tex] \large{ \begin{cases} y = 5x - 10 \\ y = - 3x + 14 \end{cases}}[/tex]
Then combine both equations
[tex] \large{5x - 10 = - 3x + 14} \\ \large{5x + 3x = 10 + 14} \\ \large{8x = 24} \\ \large{x = 3}[/tex]
Substitute x = 3 in one of given equations. I will substitute x = 3 in y = 5x-10
[tex] \large{y = 5x - 10} \\ \large{y = 5(3) - 10} \\ \large{y = 15 - 10} \\ \large{y = 5}[/tex]
Hope this helps!
