Answered

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ommon Unit Assessment (MC) I 4 of 12
Christopher determines the system of s(x) and (x) has only one solution. Which system is Christopher solving?
A
X +3
s(x) =
X-5
+1 and t(x) = x +3 +2
ОВ.
s(x) = x2
and t(x) = In(x +7)+4
C. s(x) = 2x42 -5 and t(x) = -x +31+2
OD. $(x) = (x +3 -1 and t(x) = 2x - 5

Sagot :

Answer:

D

Step-by-step explanation:

I had the same question and I got this right

Christopher is solving a system of equations that has one solution and can be seen in Option C.

What is a system of equations?

A system of equations is two or more equations that can be solved together to get a unique solution. In this situation, the power of the equation must be in one degree.

A quadratic equation is the second-order degree algebraic expression in a variable.

s(x) = 2x42 -5 and t(x) = -x +31+2

However, if their power is not in one degree, the quadratic equation produces two solutions.

From the given options, we can see that only option c is not a quadratic equation, Hence, it is the right answer.

Learn more about systems of equations here;

brainly.com/question/14323743

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