Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

What is the total number of grams of solute in 500 milliliters of 1M CH3COOH (formula mass = 60)?​

Sagot :

samueladesida43

Answer:

30 grams

Explanation:

Molarity of a solution represents its molar concentration, and can be calculated by using the formula as follows:

Molarity (M) = number of moles (n) ÷ volume (V)

Based on the information provided, volume of solution = 500 milliliters, molarity = 1M

Volume of solution in liters = 500mL ÷ 1000 = 0.50L

Molarity = n/V

1 = n/0.50

n = 0.50moles

Using mole = mass/molar mass

Molar mass of CH3COOH (acetic acid) = 60g/mol

Mass = mole × molar mass

mass = 0.50 × 60

mass = 30 grams.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.