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Given right triangle HJK, which of the
following ratios is equivalent to cosH?


Given Right Triangle HJK Which Of The Following Ratios Is Equivalent To CosH class=

Sagot :

Answer:

cosH = JH/KH

Step-by-step explanation:

coa refers to base by hypotenuse

for H,

the base is JH and the hypotenuse is KH.

In the given right angled triangle cos H is equivalent to sin K

What is right angled triangle?

A triangle in which one of the interior angles is 90° is called a right triangle

Here,

Cos H =  Adjacent side / Hypotenuse = [tex]\frac{JH}{KH}[/tex]

In the given option

sin K = Opposite side / Hypotenuse[tex]=\frac{JH}{KH}[/tex]

Therefore Cos H is equivalent to the sin K

Hence, sin K is equivalent to the cos H

Learn more about right angled triangle here

https://brainly.com/question/3770177

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