charmainenmoon
Answered

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Solve by Substitution

y= -3/2x -4

y= -1/2x =1

Sagot :

[tex]\begin{cases}y= - \frac{3}{2}x -4 \\ y= - \frac{1 }{2}x +1 \end{cases}\\ \\\begin{cases}y= - \frac{3}{2}x -4 \\ - \frac{3}{2}x -4 = - \frac{1 }{2}x +1 \end{cases}\\ \\\begin{cases}y= - \frac{3}{2}x -4 \\ - \frac{3}{2}x +\frac{1 }{2}x=1+4 \end{cases}\\ \\ \begin{cases}y= - \frac{3}{2}x -4 \\ - \frac{2}{2}x=5 \end{cases}[/tex]

[tex]\begin{cases}y= - \frac{3}{2}x -4 \\ - x=5/*(-1) \end{cases}\\ \\ \begin{cases}y= - \frac{3}{2}*(-5)-4 \\ x=-5 \end{cases}\\ \\ \begin{cases}y= \frac{15}{2}-4 \\ x=-5 \end{cases}\\ \\ \begin{cases}y= 7\frac{1}{2}-4 \\ x=-5 \end{cases}\\ \\ \begin{cases}y= 3\frac{1 }{2} \\ x=-5 \end{cases}\\ \\[/tex]
[tex] \left\{\begin{array}{ccc}y=-\frac{3}{2}x-4\\\\y=-\frac{1}{2}x+1\end{array}\right\\\\-\frac{3}{2}x-4=-\frac{1}{2}x+1\ /\cdot2\\\\-3x-8=-x+2\\\\-3x+x=2+8\\\\-2x=10\ /:(-2)\\\\x=-5\\\\y=-\frac{1}{2}\cdot(-5)+1=2,5+1=3,5\\\\ \left\{\begin{array}{ccc}x=-5\\y=3,5\end{array}\right[/tex]
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