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Sagot :
Answer: The decay constant for C14 is [tex]0.000121years^{-1}[/tex]
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{5730years}=0.000121years^{-1}[/tex]
The decay constant for C14 is [tex]0.000121years^{-1}[/tex]
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