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How much chalcopyrite had be mined to produce 100 pennies if each reaction involving copper proceeded in 69.00 % yield?

Sagot :

codedmog101

2636.06 g

Explanation:

For this question, there are three chemical equations, these balnced chemical equation are given below:

Reaction 1 => 2 CuFeS₂ + 30₂ -------------------------------------> 2CuS + 2Fe0 + 2S0₂

Reaction 2 => 2 CuS -------------------------------------------------------> Cu₂S + S

Reaction 3 =>  Cu₂S + S + 2O₂ --------------------> 2Cu + 2SO₂

It is given from the question above that each reaction involving copper proceeded in 69.00 % yield = 0.69.

The number of moles Cu₂S = 2.36/0.69 = 3.42 mol.

The number of moles of CuS from Cu₂S [from the second reaction] = 2 × 3.42 = 6.84 mol.

For the 3rd reaction and the 2nd reaction , the yield = 0.69.

The required number of moles of CuS = 6.84/ 0.69 = 9.91 mol.

The number of moles of CuFeS₂ = 9.91 /0.69 = 14.36 mol.

The amount of chalcopyrite had be mined to produce 100 pennies = 14.36 × 183.54 = 2636.06 g

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