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According to the following reaction, how many grams of iron(II) chloride will be formed upon the complete reaction of 21.6 grams of hydrochloric acid with excess iron?
iron (s) + oxygen (g) Arrow.gifiron(II) oxide (s)

Sagot :

Eduard22sly

Answer:

37.58 g of FeCl₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Fe + 2HCl —> FeCl₂ + H₂

Next, we shall determine the mass of HCl that reacted and the mass of FeCl₂ produced from the balanced equation. This is can be obtained as follow:

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Mass of HCl from the balanced equation = 2 × 36.5 = 73 g

Molar mass of FeCl₂ = 56 + (2×35.5)

= 56 + 71

= 127 g/mol

Mass of FeCl₂ from the balanced equation = 1 × 127 = 127 g

SUMMARY:

From the balanced equation above,

73 g of HCl reacted to produced 127 g of FeCl₂.

Finally, we shall determine the mass of FeCl₂ produced by the reaction of 21.6 g of HCl. This can be obtained as follow:

From the balanced equation above,

73 g of HCl reacted to produced 127 g of FeCl₂.

Therefore, 21.6 g of HCl will react to produce = (21.6 × 127)/73 = 37.58 g of FeCl₂.

Thus, 37.58 g of FeCl₂ were obtained from the reaction.

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