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What is n in the equstion?
n^2+n+2=0

Sagot :

lindsaycarballo57

Answer:

No Solution

Step-by-step explanation:

The steps are in the (2) pictures below.

View image lindsaycarballo57
View image lindsaycarballo57

✐ Answer:

[tex]n^2+n+2=0\quad :\quad n=-\frac{1}{2}+i\frac{\sqrt{7}}{2},\:n=-\frac{1}{2}-i\frac{\sqrt{7}}{2}[/tex]

✍️Steps:--

✰ [tex]n^2+n+2=0[/tex]

[tex]n_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:2}}{2\cdot \:1}[/tex]

[tex]n_{1,\:2}=\frac{-1\pm \sqrt{7}i}{2\cdot \:1}[/tex]

[tex]n_1=\frac{-1+\sqrt{7}i}{2\cdot \:1},\:n_2=\frac{-1-\sqrt{7}i}{2\cdot \:1}[/tex]

[tex]\frac{-1+\sqrt{7}i}{2\cdot \:1}[/tex]

[tex]=\frac{-1+\sqrt{7}i}{2}[/tex]

[tex]=-\frac{1}{2}+\frac{\sqrt{7}}{2}[/tex]

[tex]\frac{-1-\sqrt{7}i}{2\cdot \:1}[/tex]

[tex]=\frac{-1-\sqrt{7}i}{2}[/tex]

[tex]=-\frac{1}{2}-\frac{\sqrt{7}}{2}[/tex]

[tex]n=-\frac{1}{2}+i\frac{\sqrt{7}}{2},\:n=-\frac{1}{2}-i\frac{\sqrt{7}}{2}[/tex]

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hope it helps...

have a great day!!

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