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Fe2O3(s) + 3CO(g) → 3CO2(g) + 2Fe(s)

If 6 moles of CO reacted with excess Fe2O3, then how many moles of Fe were produced?


Sagot :

Answer:

4 moles Fe(s)

Explanation:

Fe₂O₃(s) + 3CO(g) → 3CO₂(g) + 2Fe(s)

Reaction shows a 3:2 ratio between CO(g) & Fe(s) ...

∴moles of Fe(s) produced = 2/3(6) moles Fe(s) produced = 4 moles Fe(s)