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Mohan is a farmer. He has a rectangular field of length 65m and width15m.

He digs a circular flower bed of radius of 7m at the field( π=22/7 ).

a) Find the area of the flower bed.


plese answer fast


b) Find the area of the remaining portion of the field.

c) Find the cost of levelling the remaining field at the rate of ₹5 per sq m.

Sagot :

MrRoyal

Answer:

(a) [tex]Area = 154m^2[/tex]

(b) [tex]Remaining\ portion = 821m^2[/tex]

(c) [tex]Cost = 4105[/tex]

Step-by-step explanation:

Solving (a): The area of the flower bed

Given

[tex]r = 7m[/tex]

[tex]\pi = 22/7[/tex]

The area is:

[tex]Area = \pi r^2[/tex]

[tex]Area = 22/7 * 7^2[/tex]

[tex]Area = 154m^2[/tex]

Solving (b): The area of the remaining portion

Given

[tex]Length= 65m[/tex]

[tex]Width = 15m[/tex]

First, we calculate the field area

[tex]Area = Length * Width[/tex]

[tex]Area = 65m * 15m[/tex]

[tex]Area = 975m^2[/tex]

Subtract the area of the flower pot from the filed area to get the area of the remaining portion

[tex]Remaining\ portion = 975m^2-154m^2[/tex]

[tex]Remaining\ portion = 821m^2[/tex]

Solving (c): The cost of leveling the remaining field

Given

Rate = 5 per square meter

In (b) above, the area is 821m^2

So, the cost will be:

[tex]Cost = 821 * 5[/tex]

[tex]Cost = 4105[/tex]

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