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Given the reaction:
4 NH3 + 5 O2 → 4 NO + 6 H2O
If you start with 100.0 grams of NH3, how many grams of water are produced?


Sagot :

Answer:

hi

Explanation:

[tex]100g \: ammonia \times \frac{1 \: mol \: ammonia}{17 \: g \: ammonia} \times \frac{6 \: mol \: water}{4 \: mol \: ammonia} \times \frac{18g \: water}{1mol \: water} = 158.82g \: water[/tex]

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